Matematika Sekolah Menengah Atas Diketahui fungsi f:R-R dan g: R-R dirumuskan denganF(x)=3x²+x-7 dan g(x)=2x + 1 , maka (gof)(x) =a.3x²+2x+14 B.3x2 + 2x - 14C.6x²+2x + 14D. 6x²+2x+13E.6x2 +2x-13​

melissagreenulv – March 08, 2023

Diketahui fungsi f:R-R dan g: R-R dirumuskan dengan
F(x)=3x²+x-7 dan g(x)=2x + 1 , maka (gof)(x) =
a.3x²+2x+14
B.3x2 + 2x - 14
C.6x²+2x + 14
D. 6x²+2x+13
E.6x2 +2x-13​

[tex] \mathbb \color{aqua} \underbrace{JAWABAN}[/tex]

E. 6x² + 2x - 13

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[tex] \mathbb \color{orange} \underbrace{PENYELESAIAN}[/tex]

[tex] \underline{ \overline{ \boxed{ \bold{diketahui}}}}[/tex]

• f(x) = 3x² + x - 7
• g(x) = 2x + 1

[tex] \\ \underline{ \overline{ \boxed{ \bold{ditanya}}}}[/tex]

• (g o f)(x)

[tex] \\ \underline{ \overline{ \boxed{ \bold{jawab}}}}[/tex]

[tex] \begin{aligned} \sf (g \circ f)(x) &= \sf g(f(x)) \\ &= \sf g(3 {x}^{2} + x - 7) \\ &= \sf 2(3 {x}^{2} + x - 7) + 1 \\ &= \sf {6x}^{2} + 2x - 14 + 1 \\ &= \bold{{6x}^{2} + 2x - 13} \end{aligned}[/tex]

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[tex] \mathbb \color{red} \underbrace{KESIMPULAN}[/tex]

Jadi, nilai (g o f)(x) adalah 6x² + 2x - 13

[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} [/tex]

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